Find x if 13*|2x+1|=26

We'll solve the equation, expressing first the
modulus.

Case 1:

l 2x + 1 l =
2x + 1 for 2x + 1 >= 0

2x >=
-1

x >= -1/2

Now, we'll
solve the equation:

13(2x + 1) =
26

We'll divide by 13:

2x + 1
= 2

2x = 2-1

x =
1/2

Since x =1/2 is in the interval of
admissible values,[-1/2, +infinite], we'll accept it.

Case
2:

l 2x + 1l = -2x - 1 for 2x +
1 < 0

2x <
-1

x < -1/2

Now, we'll
solve the equation:

13(-2x - 1) =
26

-2x - 1 = 2

 -2x =
3

x =
-3/2

Since x = -3/2 is in the interval of
admissible values, (-infinite, -1/2), we'll accept it.