Q: 3 l x-3 l + 4 = 10 We have to find
x.
Solution:
We subtract 4
from both sides of the equation:
3 |x-3| = 10-4
=6.
3|x-3| = 6.
We divide
both sides of 3|x-3| = 6, by 3:
|x-3| =
2.
If x> 3, then |x-3| = x-3 = 2
.
So x- 3 = 2, Or x = 5.
If
x< 3, then |x-3| = 3-x = 2.
So 3-2 = x. Or x=
1.
So x= 1, or x =
5.
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