When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2– 3y ?

Given the equations:

3x^2 -
2y

2x^2 - 3y

Also we know that
x= 3 and y= 5

We need to know the difference in values
between both equations.

First we will substitute x and y
values in each equation.

==> 3x^2 -2y = 3*(3^2) -
2*5 = 27 -10= 17

==> 2x^2 -3y = 2*(3^2) - 3*5 =
18-15 = 3

Now we will calculate the difference between both
values.

==> 17 -3 =
14.

Then the values of 3x^2 -2y exceeds the
values of 2x^2 -3y by 14.