17x + 5 >= -6x^2
First
we will move -6x^2 to the left side so the right side is
0.
==> 6x^2 + 17x + 5 >=
0
Now we have a quadratic function, we will use the
quadratic formula to find the roots.
==> x1= ( -17 +
sqrt(289-4*6*5) / 2*6
= (-17 + 13) / 12 =
-4/12 = -1/3
==> ( x+1/3 ) Or ( 3x+1) is a factor of
the function.
==> x2= ( -17-13) /12 = -30/12 =
-5/2
==> (x+5/2) OR (2x + 5) is a
factor.
==> ( 2x+5) ( 3x+1)
>=0
Then ( 2x+5) >= 0 and ( 3x+1)
>=0
==> x >= -5/2 and x>=
-1/3
==> x = [ -1/3,
inf)
OR:
x =<-5/2
and x=< =-1/3
==> x = (-inf,
-5/2]
==> x = (-inf, -5/2] U [-1/3,
inf)
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