sin^2 y = 5siny - 6
We will
move all terms to the left side so the right side is
0.
==> sin^2 y - 5siny + 6 =
0
Now let us assume that u=
siny
==> u^2 - 5u + 6 =
0
Let us factor.
==>
(u-2)(u-3) = 0
==> u= 2 ==> siny =
2
==> u= 3 ==> siny =
3
Both solutions are invalid because the the values of sine
must be between -1 and 1.
==> -1 =< siny
=< 1
Then, the function has no
solution.
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