We'll use substitution technique to solve the
integral.
We'll put x - 2 =
t.
We'll differentiate both
sides:
dx = dt
We'll re-write
the integral in t:
Int dx/(x-2)^1/3 = Int
dt/t^1/3
We'll use the negative power
rule:
1/t^1/3 = t^(-1/3)
Int
dt/t^1/3 = Int t^(-1/3)dt
Int t^(-1/3)dt = t^(-1/3 +
1)/(-1/3 + 1) + C
Int t^(-1/3)dt = t^(2/3)/(2/3) +
C
Int dx/(x-2)^1/3 = [3(x-2)^(2/3)]/2 +
C
No comments:
Post a Comment