A square is inscribed in a circle, side of the square is 2*squareroot2. What is the circumference of the circle in terms of pi.

Given that the side of the square is
2sqrt2.

Then, we know that the diagonal pf the square is
the diagonal of the circle.

Let us
calculate.

The diagonal = sqrt(side^2 +
side^2)

                     = sqrt( 2sqrt2)^2 +
(2sqrt2)^2

                    = sqrt ( 8 +8) = sqrt 16 =
4

Then, the diagonal of the circle is 4
units.

Now we need to find the circumference is the
circle.

We know that the circumference is given
by:

C = 2*r *pi

But r =
diagonal/2 = 4/2 = 2

==> C = 2*2 * pi =
4pi

Then, the circumference of the circle is
4*pi units.