a + 2b = 2
................(1)
2a -3b = 4
.................(2)
We will use the elimination method to
solve.
We will multiply (1) by -2 and add to
(2).
==> -2a -4b = -4
.....................-2*(1)
==> 2a -3b = 4
.....................(2)
==> -7b = 0 ==> b=
0
Now to calculate a we will substitute into
(1).
==> a + 2b = 2 ==> a + 0 + 2 ==>
a = 2
==> a = 2
Then
the answer to the system is :
a = 2 and
b= 0
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