Friday, December 5, 2014

What is tanx if 2sinx - 5cosx = 0 ( use right angle triangle ) ?

According to the Pythagorean theorem in a right angle
triangle:


(sin x)^2 + (cos x)^2 =
1


If we'll divide the expression by (cos x)^2, we'll
get:


(sin x)^2/(cos x)^2 + 1 = 1/(cos
x)^2


(tan x)^2 = 1/(cos x)^2  -
1


By definition, the trigonometric function tangent is a
ratio between the opposite cathetus and the adjacent
cathetus.


2sinx - 5cosx =
0


2sin x = 5cos x


If we divide
the  entire expression by 5 cos x, we'll get:


(2/5) (sin
x/cos x) = 1


We'll substitute the ratio sin x/cos x = tan
x


(2/5)* tan x =
1


tan x =
5/2

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