We'll write y = f(x) and we'll compute the indefinite
integral of f(x):
Int f(x)dx = Int (3x^2 + 2x
-1)dx
We'll apply the property of integral to be additive
and we'll get:
Int (3x^2 + 2x -1)dx = Int 3x^2dx + Int
2xdx - Int dx
We'll re-write the sum of
integrals:
Int (3x^2 + 2x -1)dx = 3Int x^2dx + 2Int xdx -
Int dx
Int (3x^2 + 2x -1)dx = 3*x^3/3 + 2*x^2/2 - x +
C
We'll simplify and we'll get the indefinite integral of
y=3x^2+2x-1:
Int (3x^2 + 2x -1)dx = x^3 +
x^2 - x + C
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