We'll have to show that for any positive number epsilon,
there is N = N(epsilon), so that:
|an - 1/5| <
epsilon for any n > N(epsilon)
We'll substitute an
by it's given expression:
|(n+1)/(5n+2) - 1/5| =
|(n+1-5n-2)/5(5n+2)| = 3/5(5n+2)
We'll get the
inequality:
3/5(5n+2) <
epsilon
3 < 5 epsilon (5n +
2)
We'll remove the
bracktes:
3 < 25*epsilon*n + 10
epsilon
We'll subtract 10
epsilon:
25*epsilon*n > 3 - 10
epsilon
n > (3 - 10 epsilon)/25
epsilon
N(epsilon) = 3/25epsilon -
2/5
For all terms that have n >
N(epsilon) = 3/25epsilon - 2/5,
|an - 1/5| <
epsilon
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