Solve. Round answer to 2 decimal places. 7^(3x) = 8^(2x)

We have to solve 7^(3x) =
8^(2x)

Now the base of the two terms are not the same, so
we use logarithms.

Take the logarithm of both the
sides.

log( 7^(3x)) =
log(8^(2x))

we use the relation log (a^b) = b*log
a

=> 3x * log 7 = 2x * log
8

=> 3x * log 7 - 2x * log 8 =
0

=> x* (3 * log 7 - 2 * log 8) =
0

=> x = 0/ (3 * log 7 - 2 * log
8)

=> x = 0

Therefore
the only possible value for x is x =
0