We'll write the linear
function:
f(x) = ax + b
To
determine the function, we'll have to determine the coefficients a and
b.
For this reason, we'll use the constraint given by
enunciation:
f(x+2)*f(x-2) =
x^2-2x-3
We'll write
f(x+2):
f(x+2) = a(x+2) +
b
f(x+2) = ax + 2a + b
(1)
We'll write f(x-2):
f(x-2)
= a(x-2) + b
f(x-2) = ax + b - 2a
(2)
We'll multiply (1) by
(2):
f(x+2)*f(x-2) = (ax + 2a + b)(ax + b - 2a) = (ax+b)^2
- (2a)^2
We'll expand the
squares:
f(x+2)*f(x-2) = a^2*x^2 + 2abx + b^2 - 4a^2
(3)
But f(x+2)*f(x-2) = x^2-2x-3
(4)
We'll put (3) =
(4)
a^2*x^2 + 2abx + b^2 - 4a^2 = x^2 - 2x -
3
a^2 = 1
a = -1 or a =
1
2ab = -2
ab =
-1
If a = 1 => b =
-1
If a = -1 => b =
1
So, the linear function could
be:
f(x) = x - 1, for a = 1 and b =
-1
or
f(x)
= -x + 1, for a = -1 and b = 1.
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