Thursday, March 10, 2011

What are all the critical points of f(x)=sinx+cosx ? 0=

The critical points are determined by differentiating the
function and equating the derivative to 0. It is solved to determine
x.


f(x) = sin x + cos x


f'(x)
= cos x - sin x = 0


=> cos x = sin
x


=> tan x =
1


=> x = arc tan
1


=> x = pi/4 ,
5*pi/4


At x = pi/4 , f(x) = sqrt
2


at x = 5*pi/4, f(x) = -sqrt
2


The critical points are at x = pi/4  and x
= 5*pi/4, and the extreme values are (pi/4, sqrt 2) and (5*pi/4,-sqrt
2).

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