Wednesday, March 16, 2011

Line L passes through the points (4 , -5) and (3 , 7). Find the slope of any line perpendicular to line L.

Given the points ( 4, -5) and the point ( 3, 7) passes
through line L.


We need to find the slope of any
perpendicular line to L.


First we will determine the slope
of L.


We know that:


m =
(y2-y1)/(x2-x1) = (7+5) / (3-4) = 12/-1 = -12


Now we know
that the product of the slopes of two perpendicular line is
-1.


==> Let m1 be the slope of any perpendicular
line.


==> m * m1 =
-1


==> -12 * m1 =
-1


==> m1=
1/12


The slope of any perpendicular line to L
is 1/12.

No comments:

Post a Comment

Calculate tan(x-y), if sin x=1/2 and sin y=1/3. 0

We'll write the formula of the tangent of difference of 2 angles. tan (x-y) = (tan x - tan y)/(1 + tan x*tan y) ...