Given the curve f(x) = x^3 -
            5
We need to find the definite integral on the interval [1,
            2].
Let us intergrate
            f(x).
Let F(x) = intg
            f(x)
==> The defininte integral is
            :
I = F(2) - F(1).
==>
            F(x) = intg (x^3 - 5) dx
              = intg x^3 dx - intg
            5 dx
               = x^4/4 - 5x +
            C
==> F(2) = 2^4/4 - 5*2  +
            C
              = 4 - 10 + c = -6 +
            c
==> F(1) = 1/4 - 5 + C = -19/4 +
            C
==> I = -6 + 19/4 = ( -24 + 19) /4 =
            -5/4
==> Then, the integral is I =
            -5/4
 
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