We also could expand the binomial and then we'll
differentiate each term of the polynomial.
(x-1)^4 = x^4 -
4x^3 + 6x^2 - 4x + 1 (1)
Now, we'll multiply (1) by
5x:
5x(x-1)^4 = 5x(x^4 - 4x^3 + 6x^2 - 4x +
1)
5x(x-1)^4 = 5x^5 - 20x^4 + 30x^3 - 20x^2 +
5x
We'll differentiate with respect to x and we'll
get:
f'(x) = 25x^4 - 80x^3 + 90x^2 - 40x +
5
We'll factorize by
5:
f'(x) = 5(5x^4 - 16x^3 + 18x^2 - 8x +
1)
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