What is the new average in the following case?A set of n numbers has an average value of the terms equal to 45. When two new terms are added to the...

Let there be n terms in the set. The average value is 45;
therefore the sum of the n terms is 45n.

The addition of
two terms a and b to the set, increases the total sum of the terms to 45n + a + b and
their average value becomes (45n + a + b)/ (n + 2) which is equal to 45 + 4 as
given.

So a + b = 49(n + 2) – 45n = 49n + 98 – 45n = 4n +
98

When the terms with the same value as those added are
removed from the set the total sum of the terms in the set is given by 45n – 4n – 98.
The average is (41n – 98)/ (n - 2).

The change in the
average is dependent on the number of terms in the set.