Problem A) The net external force will be found by using
Newton's 2nd Law. Net force is equal to mass times acceleration. We know the mass is
2.0 kg, the acceleration must be found using kinematics equations. You know the intial
velocity is zero, the distance is 0.85 m and the time is 0.5 s. Use the equation x =
v_i * t + (1/2) a t^2
0.85 = (1/2) a
(0.5)^2
a = 1.7/0.25 = 6.8
m/s^2
B) find the net force by adding the two
vectors. The vectors are perpendicular so you can add them using the pythagorean
theorem.
(390)^2 + 180^2 = 429.5 N (net
force)
acceleration = net force/mass = 429.5/270 = 1.59
m/s^2
the direction is found using
trigonometry
The inverse tangent of (390/180) gives the
angle above east that the acceleration vector has, which is 65.2 degrees north of
east
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