We have to solve sqrt ( 3x - 2)^2 <
5
=> (3x - 2)^2 <
25
Now (3x - 2)^2 can be less than 25 if 3x - 2 is less
than sqrt 5 or if 3x - 2 is greater than - sqrt 5
This
gives two inequalities
3x - 2 <
5
=> 3x <
7
=> x < 7/3
and
3x - 2 > -5
=> 3x >
-3
=> x >
-3/3
=> x >
-1
So we have -1 < x <
7/3
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