What is x if 8^(4x-6)-1/64=0 ?

We'll write 64 = 8^2, so 1/64 =
1/8^2

We'll apply the rule of negative
power:

1/8^2 = 8^-2

We'll
re-write the equation:

8^(4x-6) =
8^-2

Since the bases are matching, we'll apply the one to
one property of exponential functions:

4x - 6 =
-2

We'll isolate x to the left
side:

4x = 6 - 2

4x =
4

We'll divide by 4:

x =
1

The only solution of the equation is x =
1.