Friday, June 21, 2013

What is x if loga x= loga 7+loga 3-loga 11?

To determine x, we'll  apply the product and quotient rule
of logarithms:


log(b*c) = logb +
logc


loga 7+loga 3 = loga(7*3) = loga
21


The expression will
become:


loga x= loga 21 - loga
11


log(b/c) =  logb -
logc


loga 21 - loga 11 =
loga(21/11)


The expression will
become:


loga x =
loga(21/11)


Since the bases are matching, we'll apply the
one to one rule:


x =
21/11

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