We'll use the chain rule to differentiate the given
function:
f'(x) =
{[cos(x^3+13)]^3}'
We'll calculate the first
derivative applying the power rule first, then we'll differentiate the cosine function
and, in the end, we'll differentiate the expression
x^3+13.
f'(x) =
3[cos(x^3+13)]^2*[-sin(x^3+13)]*(x^3+13)'
f'(x) =
3[cos(x^3+13)]^2*[-sin(x^3+13)]*(3x^2)
f'(x)
= -9x^2*[cos(x^3+13)]^2*[sin(x^3+13)]
We can
re-write [cos(x^3+13)]^2 = 1 -
[sin(x^3+13)]^2
f'(x) =
-9x^2*[sin(x^3+13)]*{1 - [sin(x^3+13)]^2}
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