If x^2+ kx - 6 = (x - 2)(x + 3), then k = ?

Given that x^2 + kx - 6 =
(x-2)(x+3)

We need to find
k.

First we will need to open the brackets on the left side
and then compare the terms.

==> x^2 + kx -6 = x^2
-2x + 3x - 6

==> x^2 + kx -6 = x^2 + x
-6

Now we will add 6 to both
sides.

==> x^2 + kx = x^2 +
x

Now we will subtract
x^2

==> kx = x

Now we
will subtract x from both sides.

==> kx -x =
0

Now we will factor
x.

==> x (k-1) = 0

x
can not be zero.

Then k-1 = 0  ==> k=
1

Then the value of k is
1.