Find x if (x^1/3)^(logx x^2 +2)=2log3 27

(x^1/3)&(logx x^2 +2) = 2log3
27

We will use logarithm and exponent properties tp
solve.

First, we know that x^a^b =
x^ab

==> x^(1/3)*(logx x^2 + 2) = 2log3
3^3

Now we know that log x^a = alog
x

==> x^(1/3)*(2logx x + 2) = 2*3log3
3

But we know that logx x = 1 and log3 3 =
1

==> x^(1/3)*(2+2) =
6*1

==> x^4/3 = 6

Now
we will raise to the power 3/4

==> x =
6^3/4