Tuesday, October 12, 2010

What is the integral of sin ^3 x.

We have to determine the value of Int [ (sin x)^3
dx]


Int [ (sin x)^3
dx]


=> Int [ (sin x)^2* sin x
dx]


=> Int [ (1 – (cos x)^2 )* sin x
dx]


let u = cos x => du = -sin x
dx


=> Int [ (1 – u^2 )*
(-du)]


=> u^3/3 – u +
C


substitute u = cos
x


=> ( cos x)^3 / 3 – cos x +
C


The integral is (cos x)^3/ 3 – cos x +
C

No comments:

Post a Comment

Calculate tan(x-y), if sin x=1/2 and sin y=1/3. 0

We'll write the formula of the tangent of difference of 2 angles. tan (x-y) = (tan x - tan y)/(1 + tan x*tan y) ...