We have to determine the value of Int [ (sin x)^3
            dx]
Int [ (sin x)^3
            dx]
=> Int [ (sin x)^2* sin x
            dx]
=> Int [ (1 – (cos x)^2 )* sin x
            dx]
let u = cos x => du = -sin x
            dx
=> Int [ (1 – u^2 )*
            (-du)]
=> u^3/3 – u +
            C
substitute u = cos
            x
=> ( cos x)^3 / 3 – cos x +
            C
The integral is (cos x)^3/ 3 – cos x +
            C
 
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