Solve using the quadratic formula: 3x^2 -5x -4 = 0

The roots x1 and x2 of the quadratic equation ax^2+bx+c =
0 is given by the formula:

x1 = {-b+sqrt(b^2-4ac)}/2
and

x2 =
-{b+sqrt(b^2-4ac)}/2.

The given quadratic equation is
3x^2-5x-4 = 0.

So a = 3, b= -5 and c=
-4.

So using the formula we get the two
roots:

x1 = {-(-5)+sqrt(-5)^2-4*3(-4)}/2*3 =
{5+sqrt(25+48)}/6

x1 =
{5+sqrt(73)}/6.

x2 =
{5-sqrt(73)}/6.