What is the velocity of the bullet of mass 10 g if it raises a mass of 5 kg when it hits it by 10 cm?

The mass of the bullet is 10 g. The mass that is hung is
of 5 kg. When the bullet strikes the mass its height increases by 10
cm.

The potential energy of the mass changes by m*g*h =
5*(10/100)*9.8

This potential energy is imparted by the
bullet that strikes the hung mass.

It does not make a
difference if the bullet is embedded in the 5-kg mass or has passed through it because
its mass of 10 g is negligible compared to that of the mass that is
hung.

The kinetic energy in a body of mass 10 g travelling
at a velocity of V m/s is (1/2)*(10/1000)*V^2

This is equal
to the change in the kinetic energy

=>
(1/2)*(10/1000)*V^2 = 5*(10/100)*9.8

=> V^2 =
(100)*9.8

=> V^2 =
98

=> V = sqrt
98

=> V = 7 * sqrt 2
m/s

The velocity of the bullet is 7* sqrt 2
m/s