Monday, January 25, 2016

How do I balance the equation: C6H5COOH + O2 = CO2 + H2O? Also, are there a general set of rules that I can adopt.

The equation that needs to be balanced is: C6H5COOH + O2
--> CO2 + H2O


To balance these kind of equations
follow these steps:


  • First balance the carbon
    atoms on both the sides. So the number of CO2 molecules on the right hand side would be
    equal to the number of C atoms on the left hand
    side.

  • Next balance the number of
    hydrogen atoms on both the sides. The number of H2O molecules on the right hand side
    would be half the number of H atoms on the left hand
    side.

  • Now add the number of O atoms
    on the right hand side, and subtract the O atoms not present as O2 molecules on the left
    hand side. Half of the number you get by doing this is the number of O2 molecules on the
    left hand side.

  • In case it is not
    possible to balance the equation as you get fractions for any of the molecules you may
    have to use multiples of the numbers.

Using the
steps listed above, the balanced form of the given equation
is:


2C6H5COOH + 15O2 --> 14CO2 +
6H2O

No comments:

Post a Comment

Calculate tan(x-y), if sin x=1/2 and sin y=1/3. 0

We'll write the formula of the tangent of difference of 2 angles. tan (x-y) = (tan x - tan y)/(1 + tan x*tan y) ...