Given the sum of two numbers = 3 and the product = 2 find the sum of the squares of the numbers.

We'll note the sum as S and the product by
P.

To determine the numbers, we'll form the quadratic
equation and we'll determine it's roots.

x^2 - Sx + P =
0

S = 3 and  P = 2

We'll
substitute them into equation:

x^2 - 3x + 2 =
0

We'll apply the quadratic
formula:

x1  =[3 + sqrt(9 -
8)]/2

x1 = (3+1)/2

x1 =
2

x2 = (3-1)/2

x2 =
1

The numbers whose sum is 3 and product is 2
are: 1 and 2.

S = 1 + 2 =
3

P = 1*2 =
2