Sunday, December 13, 2015

Is this correct or incorrect?

If the given integration is correct the derivative
of


(u/8)*(2u^2 - a^2)sqrt( a^2 - u^2) + (a^4/8)arc sin
(u/a) + C


should be u^2*sqrt ( a^2 -
u^2)


[(u/8)*(2u^2 - a^2)sqrt( a^2 - u^2) + (a^4/8)arc sin
(u/a) + C]'


=> [(u/8)*(2u^2 - a^2)sqrt( a^2 - u^2)]'
+ [(a^4/8)arc sin (u/a)]'


=> [(u^3/4 - u*a^2/8)sqrt(
a^2 - u^2)]' + [(a^4/8)arc sin (u/a)]'


=> [((3/4)u^2
- a^2/8)*sqrt (a^2 - u^2) + (u^3/4 - u*a^2/8)*(-u)/sqrt (a^2 - u^2) + (a^4/8)/sqrt (a^2
- u^2)]


=>[((3/4)u^2 - a^2/8)(a^2 - u^2) + (u^3/4 -
u*a^2/8)(-u) + (a^4/8)]/sqrt (a^2 - u^2)


=>
[3u^2a^2/4 - a^4/8 - 3u^4/4 + u^2a^2/8 - u^4/4 + u^2a^2/8 + a^4/8]/ sqrt (a^2 -
u^2)


=> [u^2a^2 - u^4]/ sqrt (a^2 -
u^2)


=> u^2(a^2 - u^2)/sqrt (a^2 -
u^2)


=> u^2 sqrt (a^2 -
u^2)


Therefore the given integration is
correct.

No comments:

Post a Comment

Calculate tan(x-y), if sin x=1/2 and sin y=1/3. 0

We'll write the formula of the tangent of difference of 2 angles. tan (x-y) = (tan x - tan y)/(1 + tan x*tan y) ...