Find the net resistance in the following cases.A single strand of wire has a resistance of 5.60μΩ. 120 strands of wire are: (a) placed side by...

When two resistors with resistances R1 and R2 are
connected in series the net resistance is equal to Rn = R1 + R2. And when the two
resistors are connected in parallel the net resistance is given by 1/Rn = 1/R1 +
1/R2.

a. We have 120 resistors of 5.6 micro ohm in
parallel. The net resistance will be (5.6*10^-6) ^120/
120*5.6*10^-6

= (5.6*10^-6) ^119/ 120
ohm

b. We have 120 resistors of 5.6 micro ohm connected in
series. The net resistance is 120*5.6*10^-6

= 672*10^-6
ohm

We can see that when the wires are connected in
parallel the net resistance is a tiny fraction of what it is when are connected in
series.