Given the system:
a = 2+ b
.............(1)
b = 3c
.............(2)
a+b = c
...............(3)
We will use the substitution method to
solve.
We will substitute (2) into
(1).
==> a= 2+ b = 2 +
3c
==> a = 2+ 3C
..............(4)
Now we will substitute (2) and (3) into
(4).
==> a + b =
C
==> (2+3c) + 3c =
c
==> 2 + 6c =
c
==> 5c =
-2
==> c =
-2/5
==> b = 3c = 3*-2/5 =
-6/5
==> b =
-6/5
==> a = 2+ b = 2 - 6/5 =
4/5
==> a =
4/5
Then, the answer
is:
a= 4/5 b= -6/5 c
= -2/5
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