To factor
x^3+x^2-6x
Solution:
x^3+x^2-6x
= x*x^2+x*x-x*6
Each term is a factor of x. So we can
factor out x and rewite the given expression
as:
x(x^2+x-6)...............(1)
The
second factor x^2+x-6 in (1) by grouping the middle term could be rewritten like:
x^2+3x-2x-6=
=x(x+3)-2(x+3)
=(x+3)(x-2).
Substituting this for x^2+x-6 in (1), we get:
x(x+3)(x-2)
which is the factored form of x^3+x^2-6
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