Sunday, September 27, 2015

How to find x and y in simultaneous equations? y^2-4xy+4y=1 3x^2-2xy=1

We have to solve the simultaneous
equation


y^2 - 4xy + 4y = 1
...(1)


3x^2 - 2xy = 1
...(2)


We see that it is not possible to isolate x in terms
of y or y in terms of x using any of the equations.


In (1)
we get y = 1/(y - 4x + 4)


In (2) we get x = 1/(3x -
2y)


As this is the case, we cannot the solve the system of
simultaneous equations. Using a random solution of (1 , 1), we do get
both


y^2 - 4xy + 4y = 1 and 3x^2 - 2xy =
1


The required solution of the equations is
(1, 1)


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