Which of he following equations has the sum of its roots as 3? (A) x^2 + 3x - 5 = 0 (B) -x^2 + 3x +3 =0

We know that if ax^2 + bx + c = 0 is a quadratic equation,
x1 and x2 are the roots, Then:

1. x1 + x1 =
-b/a

2. x1*x2= c/a

Let us use
the rule to determine the roots for both equations.

For the
equation x^2 + 3x -5 = 0

==> x1+ x2 = -b/a = -3/1 =
-3

For the equation -x^2 + 3x+3 =
0

==> x1+x2 = -b/a = -3/-1 =
3

Then the equation with the sum of its roots
= 3 is (-x^2 +3x +3 = 0)