Tuesday, June 12, 2012

What is [(2^-x) - 1] divided by [(2^x) - 1] . Solve it.

We need to simplify the expression (2^-x -1) / (2^x
-1)


First , we will rerite 2^-x =
1/2^x


==> (2^-x) -1= (1/2^x) -1 = (1-2^x)/2^x=
-(2^x-1)/2^x


Now we will substitute into the
expression.


==> (2^-x)-1)/ (2^x -1) = (-2^x-1)/2^x]
/ (2^x-1)


Now we will reduce similar
terms.


==> -1/2^x / 1
-1/2^x


==> (2^-x)-1) / (2^x-1) = -1/2^x =
-2^-x


Now we will try and find the
solution.


==> -1/2^x =
0


Then, there is no solution for the equation because the
numerator is a constant numbers and can not be
zero.


Then, there is no
solution.

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