Wednesday, June 20, 2012

How can evaluate?(1+i)^2008=?

(1+i)^2008.


To simplify,
first we will rewrite the exponent.


==> ( 1+ i)^2008
= (1+ i)^(2*1004)


Now we know from exponent properties that
x^ab= (x^a)^b


==> (1+i)^(2*1004) =[
(1+i)^2]^1004


Now we will expand the
brackets.


==> (1+i)^2]^1004 = (1 + 2i+ i^2)
^1004


But we know that i^1 =
-1


==> (1+2i+i^2)^1004 =
(2i)^1004


==> (2i)^(2*502) =[ (2i)^2]^502 =
(4i^2)^502


==> (4*-1)^502 = =
4^502


==> (1+i)^2008 =
2^(1004)

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