(1+i)^2008.
To simplify,
first we will rewrite the exponent.
==> ( 1+ i)^2008
= (1+ i)^(2*1004)
Now we know from exponent properties that
x^ab= (x^a)^b
==> (1+i)^(2*1004) =[
(1+i)^2]^1004
Now we will expand the
brackets.
==> (1+i)^2]^1004 = (1 + 2i+ i^2)
^1004
But we know that i^1 =
-1
==> (1+2i+i^2)^1004 =
(2i)^1004
==> (2i)^(2*502) =[ (2i)^2]^502 =
(4i^2)^502
==> (4*-1)^502 = =
4^502
==> (1+i)^2008 =
2^(1004)
No comments:
Post a Comment