The length of a rectangular garden is 2 feet longer than 3 times its width. If the perimeter of the garden is 100 feetfind the width and the length...

Let the length of the rectangle be L, and the width be
W.

Given that the length is 2 ft longer than 3 times
w.

Then we write: L = 2 +
3w...........(1)

Also, given that the perimeter is 100
ft.

==> P = 2L + 2W =
100

We will divide by
2.

==> L + W = 50
........(2).

Now we will solve the system by
substitution.

==> 2+3W + W =
50

==> 2 + 4W =
50

==> Subtract 2 from both
sides.

==> 4W = 48

Now
divide by 4.

==> W = 48/4 =
12

==> L = 2+ 3w = 2+ 3*12 = 2+36 =
38

Then the width is 12 ft and the length is
38 ft.