Solve |2x + 1|

To draw the graph of |2x + 1| >3, remember
that

|2x +1| = 2x + 1 , when 2x + 1 >
0

and -(2x + 1) when 2x + 1 <
0

So we have two inequations
here.

2x + 1 > 3, for 2x + 1>
0

=> 2x > 2 and 2x >
-1

x > 1 satisfies
both

-(2x + 1) > 3 for 2x + 1 <
0

=> 2x + 1 <
3

=> 2x < 2 and x <
-1/2

=> x < -1/2 satisfies
both.

So the required graph would have all
values of x with x > 1 and x < -1/2