Monday, June 20, 2011

Determine if the functions converge or diverge?I dont know how to do these! Please help by explaining so I can understand! Thanks! Example:...

A sries like u1+u2+u3+.....un+..... is  said to be
convergent if its partial sum Sn = u1+u2+u3+u4+....un  has a finite limit as n
approaches infinity.


A necessary condtion for this is that
the nth term should have limit 0.


In this case the nth term
un = (5n^4)+1/((150,348n^3)+999) is


Lt (5n^4) +Lt
(1/((150,348n^3)+999) as n--> inf.


= inf+0 = inf. So
the series diverges;


Even if  you write the nth term as
(5n^4+1)/((150,348n^3)+999). The limit of this behave like  5n^4/150348n^3 as
n-->infinity. Or like


(5/150348) n which approaches
infinity as n--> infinity.


So the series
diverge.


b)


To detrmine the
nature of (convergent or otherwise) of the series 2, 1, 2/3, 2/5.... The series is
rewritten as:


2/1,   2/2, 2/3,  2/4,  2/5,  
2/6,........2/n.......... Or



So the nth term of
this series is 2/n. Which could be compared with popular series 1, 1/2, 1/3,1/4,1/5,
etc. which is divergent in the sense Su(1/n) for n=1 to inf approach
infinite.


Since each term of the given series is 2 times
the latter, the former series also diverges.

No comments:

Post a Comment

Calculate tan(x-y), if sin x=1/2 and sin y=1/3. 0

We'll write the formula of the tangent of difference of 2 angles. tan (x-y) = (tan x - tan y)/(1 + tan x*tan y) ...