Given the function f(x) = x^2 + 2x
-1
and the line y= 2x+3
We
need to find the intersection points for the curve and the
line.
Then, we need to find the point that verifies f(x)
and y.
==> f(x) =
y
==> x^2 + 2x -1 = 2x
+3
We will subtract 2x from both
sides:
==> x^2 -1 =
3
Now we will add 1 to both
sides.
==> x^2 =
4
==> x = +-2
Then,
there are two points of intersection between the curve f(x) and the line
y.
==> f(2) = 4+4-1 =
7
==> f(-2) = 4-4-1 =
-1
Then, the points of intersection
are:
(-2, -1) and (2,7)
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