Determine the maximum point of the curve y = x^2 - 8x + 16.

The maximum point of these quadratic function is
represented by the vertex of the function.

The graph of the
quadratic function is a parabola and the coordinates of the parabola vertex
are:

V(-b/2a;-delta/4a), where a,b,c are the coefficients
of the  function and delta=b^2 -4*a*c.

y=f(x)=x^2 - 8x +
16

We'll identify the
coefficients:

a=1, 2a=2,
4a=4

b=-8, c=16

delta=(-8)^2
-4*1*16

delta =64 - 64

delta =
0

V(-b/2a;-delta/4a)=V(-(-8)/2;-(0)/4)

V(-b/2a;-delta/4a)=V(4;0)

We notice that the x
coordinate is positive and y coordinate is 0, so the vertex of parabola is located on
the right side of x axis: V(4;0).