What is the surface area of the cylinder whose radius is 6 in and the height is 17 in.

Given the cylinder such that the radius of the base is (r)
= 6 in

Also, given that the height of the cylinder is (h) =
17 in.

We need to find the surface area of the
cylinder.

We know that the surface area of the cylinder is
given by the following equation.

SA = 2*area of the base +
area of the side.

==> SA = 2*A1 +
A2

Let us calculate the area of the
base.

We know that the area of the circle =
r^2*pi

==> A1 = 36*pi = 113.1
in^2

Now we need to find the area of the
sides.

A2 = circumference of the base *
h

       = 2*pi*r * h

        
= 2*6*pi*17 = 204*pi = 640.9 in^2

Now we will substitute
into the surface area.

SA = 2*A1 +
A2

     = 2*113.1 +
640.9

      = 226.2 + 640.9 = 867.1 in^2
(approx.)

Then, the surface area of the
cylinder is 867.1 in^2