What are x and y if (x-1)/i + (y+1)/2 = (x+2)/3 + (y-1)/i ?

What are x and y if (x-1)/i + (y+1)/2 = (x+2)/3 +
(y-1)/i

(x-1)/i +(y+1)/2 = (x+2)/3 +(y-i)/i. We bring both
sides to x+yi form.

(y+1)/2+(x-1)i/i^2  = (x+2)/3
+(y-1)i)/i^2.

(y+1)/2 - (x-1)i = (x+2)/3 - (y-1)i , as i^2
= 1.

We equate real parts on both sides and then equate
imaginary parts on both sides:

Real parts: (y+1)/2 =
(x+2)/3

=>3(y+1) =
2(x+2).

=> 3y-2x =
1....(1).

Imaginary parts: x-1 =
y-1.

=> x=
y.....(2).

So putting x= y in (1), we get: 3x-22x = 1. So
x= 1.

Therefore x= 1 . From (2),  y = x=
1.

So x= 1 and y = 1.