Find the x-intercepts for the parabola: y = x^2 + 4x - 3

The x-intercepts for a function are the points where the
graph of the function meets the x-axis. Here the value of f(x) is
0.

For the given equation of the parabola: y = x^2 + 4x -
3, we find the x-intercepts by equating y = 0 and solving the resulting
equation.

y = x^2 + 4x - 3 =
0

x1 = [-b + sqrt (b^2 -
4ac)]/2a

=> x1 = [ -4 + sqrt ( 16 +
12)]/2

=> -2 + sqrt 28 /
2

=> -2 + sqrt
7

x2 = -2 - sqrt
7

The x-intercepts of the parabola are at the
points ( -2 + sqrt 7 , 0) and ( -2 - sqrt 7 ,
0)