Given that g(x) =
(x-2)/(x^2-4)
We need to find the integral of
g(x).
First we will
simplify.
g(x) = (x-2)/(x-2)(x+2) =
1/(x+2)
==> g(x) =
(x+2)^-1
Now we will
integrate.
==> Intg g(x) dx = Int (x+2)^-1
dx
We will assume that u= x+2 ==> du =
dx
==> Int g(x) dx = Int 1/u du = ln u +
c
Now we will substitute back u=
x+2
==> Int g(x) = ln (x+2) +
C
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