We have the two equations x + 3y = 8 and 4x – 7y = 1. We
can see that it is not possible to multiply the equations by any number and add or
subtract them to achieve a common coefficient for x and y that can be canceled to yield
the value of x+y.
So, let’s find x and y and use that to
determine their sum.
We have x + 3y =
8
=> x = 8 –
3y
substitute this in 4x – 7y =
1
=> 4(8 – 3y) – 7y =
1
=> 32 – 12y – 7y =
1
=> -19y =
-31
=> y = 31/19
x = 8
– 3*(31/19)
=> x =
59/19
The sum x + y = 31/19 + 59/19 =
90/19
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