If the sides of a right angle triangle at B ABC are AB=6 and BC=7, find the value of cos A and cos B

Given the right angle triangle at B is ABC such
that:

AB = 6

BC=
7

Then the hypotenuse is
AC

Now we will calculate the length of the
hypotenuse.

==> AC^2 = AB^2 +
BC^2

==> AC^2 = 6^2 + 7^2 = 36+49=
85

==> AC = sqrt85

Now
let us calculate cosA and cosB

We know that cosA= adjacent/
hypotenuse.

==> cosA= AB/AC=
6/sqrt85

==> cosA= 6sqrt85 /
85

Now we know B is the right
angle.

==> B=
pi/2

==> cosB = cos(pi/2) =
0

Then the answer
is:

cosA= 6*sqrt85 /
85

cosB =
0