To determine this term, we'll have to write the formula of
the term that occupies the place k+1:
T k+1 =
C(n,k)*a^(n-k)*b^(k) (*)
We'll identify the terms a and b
from the development:
a = x^2 and b =
1/x
We don't know the place that the term occupies, so,
we'll have to determine k.
n =
9
We'll substitute all we know in the formula
(*);
T k+1 =
C(9,k)*x^[2(9-k)]*x^(-k)
We'll add the superscripts of
x:
T k+1 =
C(9,k)*x^[2(9-k)-k]
Since this term doesn't contain x,
we'll impose the constraint that the superscript to be zero, because x^0 =
1.
[2(9-k)-k] = 0
We'll remove
the brackets:
18 - 2k - k =
0
We'll combine like
terms:
-3k = -18
We'll divide
by -3:
k =
6
The term that doesn't
contain x occupies the 7th place, so it is the 7th term of
development.
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